Redox Reaction Calculator
Free redox reaction calculator for balancing oxidation-reduction reactions. Get step-by-step solutions with half-reactions, oxidation states, and electron transfer analysis. Perfect for chemistry students learning electrochemistry.
Last updated: December 15, 2024
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Balanced Redox Reaction
Balanced Equation:
Zn + Cu²⁺ → Zn²⁺ + Cu
Oxidation:
Zn → Zn²⁺ + 2e⁻
Reduction:
Cu²⁺ + 2e⁻ → Cu
Oxidation State Changes:
Zn:
0 → +2
Change: +2
Cu:
+2 → 0
Change: -2
Electrons Transferred:
2
Reaction Type:
Single Displacement
Oxidizing Agent:
Cu²⁺
Reducing Agent:
Zn
Step-by-Step Solution:
Redox Reaction Tips:
- • Oxidation: Loss of electrons (increase in oxidation number)
- • Reduction: Gain of electrons (decrease in oxidation number)
- • OIL RIG: Oxidation Is Loss, Reduction Is Gain
- • Oxidizing agent gets reduced, reducing agent gets oxidized
- • Electrons lost = electrons gained in balanced reaction
Redox Reaction Concepts
Definition
Loss of electrons, increase in oxidation number
Example: Zn → Zn²⁺ + 2e⁻
Definition
Gain of electrons, decrease in oxidation number
Example: Cu²⁺ + 2e⁻ → Cu
Mnemonic
Oxidation Is Loss, Reduction Is Gain
Helps remember electron transfer direction
Function
Causes oxidation by accepting electrons
Example: Cu²⁺ oxidizes Zn
Function
Causes reduction by donating electrons
Example: Zn reduces Cu²⁺
Purpose
Track electron transfer separately
Makes balancing easier
Quick Example Result
Zn + Cu²⁺ → Zn²⁺ + Cu:
Electrons
2
Oxidizing Agent
Cu²⁺
Reducing Agent
Zn
How to Balance Redox Reactions
Redox reactions are fundamental in chemistry, involving the transfer of electrons between species. Understanding how to balance these reactionsis crucial for electrochemistry, corrosion studies, and many industrial processes. The key is tracking electron flow and ensuring conservation of mass and charge.
The Redox Balancing Process
This systematic approach ensures proper electron conservation and balanced equations.
Oxidation Numbers
Oxidation numbers help track electron transfer. Key rules: free elements have oxidation number 0, monatomic ions have oxidation number equal to their charge, hydrogen is +1 (except in metal hydrides), oxygen is -2 (except in peroxides), and the sum of oxidation numbers in a compound equals the compound's charge.
- Free elements: oxidation number = 0
- Monatomic ions: oxidation number = ion charge
- Hydrogen: +1 (except in metal hydrides where it's -1)
- Oxygen: -2 (except in peroxides where it's -1)
- Sum of oxidation numbers = compound charge
Sources & References
- Chemistry: The Central Science - Brown, LeMay, Bursten (14th Edition)Comprehensive coverage of redox reactions and electrochemistry
- General Chemistry - Petrucci, Herring, Madura (11th Edition)Detailed explanations of oxidation states and balancing methods
- Khan Academy - Redox Reactions and ElectrochemistryVideo tutorials and practice problems on redox balancing
Need help with other chemistry topics? Check out our mole calculator and partial pressure calculator.
Get Custom Calculator for Your PlatformRedox Reaction Example
Given Reaction:
Solution Steps:
- Step 1: Identify oxidation and reduction half-reactions
- Oxidation: Zn → (loses electrons)
- Reduction: Cu²⁺ → (gains electrons)
- Step 2: Balance atoms in each half-reaction
- Step 3: Balance electrons (find LCM)
- Step 4: Add half-reactions together
- Step 5: Cancel electrons to get net equation
- Final: Zn + Cu²⁺ → Zn²⁺ + Cu
Final Balanced Reaction:
Electrons Transferred
2
Oxidizing Agent
Cu²⁺
Reducing Agent
Zn
Combustion
2H₂ + O₂ → 2H₂O
H₂ oxidized, O₂ reduced
Metal Displacement
Fe + Cu²⁺ → Fe²⁺ + Cu
Fe oxidized, Cu²⁺ reduced
Frequently Asked Questions
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